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vim-patch:8.2.0987: Vim9: cannot assign to [var; var]

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Problem:    Vim9: cannot assign to [var; var].
Solution:   Assign rest of items to a list.

9af78769ee

Co-authored-by: Bram Moolenaar <Bram@vim.org>
This commit is contained in:
zeertzjq 2023-05-04 13:54:55 +08:00
parent 24d4a82569
commit 1659cd15be
2 changed files with 12 additions and 9 deletions
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10
src/nvim/eval.c
View File

@ -3683,9 +3683,6 @@ static int eval_index(char **arg, typval_T *rettv, evalarg_T *const evalarg, boo
n1 = (int)len;
}
if (range) {
list_T *l;
listitem_T *item;
if (n2 < 0) {
n2 = (int)len + n2;
} else if (n2 >= len) {
@ -3694,12 +3691,7 @@ static int eval_index(char **arg, typval_T *rettv, evalarg_T *const evalarg, boo
if (!empty2 && (n2 < 0 || n2 + 1 < n1)) {
n2 = -1;
}
l = tv_list_alloc(n2 - n1 + 1);
item = tv_list_find(rettv->vval.v_list, n1);
while (n1++ <= n2) {
tv_list_append_tv(l, TV_LIST_ITEM_TV(item));
item = TV_LIST_ITEM_NEXT(rettv->vval.v_list, item);
}
list_T *l = tv_list_slice(rettv->vval.v_list, n1, n2);
tv_clear(rettv);
tv_list_set_ret(rettv, l);
} else {

11
src/nvim/eval/typval.c
View File

@ -765,6 +765,17 @@ int tv_list_concat(list_T *const l1, list_T *const l2, typval_T *const tv)
return OK;
}
list_T *tv_list_slice(list_T *ol, int n1, int n2)
{
list_T *l = tv_list_alloc(n2 - n1 + 1);
listitem_T *item = tv_list_find(ol, n1);
for (; n1 <= n2; n1++) {
tv_list_append_tv(l, TV_LIST_ITEM_TV(item));
item = TV_LIST_ITEM_NEXT(rettv->vval.v_list, item);
}
return l;
}
typedef struct {
char *s;
char *tofree;