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vim-patch:8.1.1061: when substitute string throws error, substitute happens anyway
Problem: When substitute string throws error, substitute happens anyway.
Solution: Skip substitution when aborting. (closes vim/vim#4161)
0e97b94875
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@ -3831,6 +3831,12 @@ static buf_T *do_sub(exarg_T *eap, proftime_T timeout,
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sublen = vim_regsub_multi(®match,
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sublen = vim_regsub_multi(®match,
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sub_firstlnum - regmatch.startpos[0].lnum,
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sub_firstlnum - regmatch.startpos[0].lnum,
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sub, sub_firstline, false, p_magic, true);
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sub, sub_firstline, false, p_magic, true);
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// If getting the substitute string caused an error, don't do
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// the replacement.
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if (aborting()) {
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goto skip;
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}
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// Don't keep flags set by a recursive call
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// Don't keep flags set by a recursive call
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subflags = subflags_save;
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subflags = subflags_save;
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if (subflags.do_count) {
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if (subflags.do_count) {
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@ -611,3 +611,33 @@ func Test_sub_replace_10()
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call assert_equal('aa2a3a', substitute('123', '1\|\ze', 'a', 'g'))
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call assert_equal('aa2a3a', substitute('123', '1\|\ze', 'a', 'g'))
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call assert_equal('1aaa', substitute('123', '1\zs\|[23]', 'a', 'g'))
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call assert_equal('1aaa', substitute('123', '1\zs\|[23]', 'a', 'g'))
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endfunc
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endfunc
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func Test_nocatch_sub_failure_handling()
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" normal error results in all replacements
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func! Foo()
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foobar
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endfunc
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new
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call setline(1, ['1 aaa', '2 aaa', '3 aaa'])
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%s/aaa/\=Foo()/g
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call assert_equal(['1 0', '2 0', '3 0'], getline(1, 3))
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" Trow without try-catch causes abort after the first line.
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" We cannot test this, since it would stop executing the test script.
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" try/catch does not result in any changes
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func! Foo()
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throw 'error'
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endfunc
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call setline(1, ['1 aaa', '2 aaa', '3 aaa'])
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let error_caught = 0
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try
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%s/aaa/\=Foo()/g
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catch
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let error_caught = 1
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endtry
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call assert_equal(1, error_caught)
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call assert_equal(['1 aaa', '2 aaa', '3 aaa'], getline(1, 3))
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bwipe!
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endfunc
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