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eval: Remove dictwatcher from watchers queue before freeing it
This fixes a use-after-free noticed by ASAN which would occur when a dictwatcher was still active on a dictionary when the dictionary was freed. fun! MakeWatch() let d = {'foo': 'bar'} call dictwatcheradd(d, 'foo', function('...')) endfun Patch-by: oni-link Closes #5930
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@ -6410,8 +6410,8 @@ static void dict_free_contents(dict_T *d) {
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while (!QUEUE_EMPTY(&d->watchers)) {
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QUEUE *w = QUEUE_HEAD(&d->watchers);
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DictWatcher *watcher = dictwatcher_node_data(w);
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dictwatcher_free(watcher);
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QUEUE_REMOVE(w);
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dictwatcher_free(watcher);
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}
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hash_clear(&d->dv_hashtab);
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@ -3,6 +3,7 @@ local clear, nvim, source = helpers.clear, helpers.nvim, helpers.source
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local eq, next_msg = helpers.eq, helpers.next_message
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local exc_exec = helpers.exc_exec
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local command = helpers.command
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local eval = helpers.eval
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describe('dictionary change notifications', function()
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@ -255,5 +256,21 @@ describe('dictionary change notifications', function()
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eq({'notification', '2b', {'key', {old = 'v2', new = 'value'}}}, next_msg())
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end)
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it('does not crash when freeing a watched dictionary', function()
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source([[
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function! Watcher(dict, key, value)
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echo a:key string(a:value)
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endfunction
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function! MakeWatch()
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let d = {'foo': 'bar'}
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call dictwatcheradd(d, 'foo', function('Watcher'))
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endfunction
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]])
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command('call MakeWatch()')
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eq(2, eval('1+1')) -- Still alive?
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end)
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end)
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end)
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