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vim-patch:8.2.2318: Vim9: string and list index work differently
Problem: Vim9: string and list index work differently.
Solution: Make string index work like list index. (closes vim/vim#7643)
e7525c5520
Co-authored-by: Bram Moolenaar <Bram@vim.org>
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parent
a44ac26c75
commit
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@ -7523,16 +7523,30 @@ int check_luafunc_name(const char *const str, const bool paren)
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/// "index" is out of range NULL is returned.
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char *char_from_string(const char *str, varnumber_T index)
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{
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size_t nbyte = 0;
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varnumber_T nchar = index;
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if (str == NULL || index < 0) {
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if (str == NULL) {
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return NULL;
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}
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size_t slen = strlen(str);
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while (nchar > 0 && nbyte < slen) {
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// do the same as for a list: a negative index counts from the end
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if (index < 0) {
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int clen = 0;
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for (size_t nbyte = 0; nbyte < slen; clen++) {
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nbyte += (size_t)utf_ptr2len(str + nbyte);
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}
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nchar = clen + index;
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if (nchar < 0) {
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// unlike list: index out of range results in empty string
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return NULL;
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}
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}
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size_t nbyte = 0;
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for (; nchar > 0 && nbyte < slen; nchar--) {
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nbyte += (size_t)utf_ptr2len(str + nbyte);
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nchar--;
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}
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if (nbyte >= slen) {
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return NULL;
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@ -859,7 +859,7 @@ int tv_list_slice_or_index(list_T *list, bool range, varnumber_T n1_arg, varnumb
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// A list index out of range is an error.
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if (!range) {
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if (verbose) {
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semsg(_(e_list_index_out_of_range_nr), (int64_t)n1);
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semsg(_(e_list_index_out_of_range_nr), (int64_t)n1_arg);
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}
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return FAIL;
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}
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