Fix ipa console filename

THe ipa console command takes an optional filename argument. The
filename argument was broken, because the implementation passed a file
object to exec() instead of a string or compiled object.

ipa console now uses compile() to compile the code with print_function
__future__ feature.

Signed-off-by: Christian Heimes <cheimes@redhat.com>
Reviewed-By: Alexander Bokovoy <abokovoy@redhat.com>

ipalib/cli.py

@@ -992,12 +992,18 @@ class console(frontend.Command):
         )
         if filename:
             try:
-                script = open(filename)
+                with open(filename) as f:
+                    source = f.read()
             except IOError as e:
                 sys.exit("%s: %s" % (e.filename, e.strerror))
             try:
-                with script:
-                    exec(script, globals(), local)
+                compiled = compile(
+                    source,
+                    filename,
+                    'exec',
+                    flags=print_function.compiler_flag
+                )
+                exec(compiled, globals(), local)
             except Exception:
                 traceback.print_exc()
                 sys.exit(1)

ipatests/test_integration/test_commands.py

@@ -164,3 +164,19 @@ class TestIPACommand(IntegrationTest):
         assert result.returncode == 0
         assert "SELinux user map order: {}".format(
             maporder) in result.stdout_text
+
+    def test_ipa_console(self):
+        result = self.master.run_command(
+            ["ipa", "console"],
+            stdin_text="api.env"
+        )
+        assert "ipalib.config.Env" in result.stdout_text
+
+        filename = tasks.upload_temp_contents(
+            self.master,
+            "print(api.env)\n"
+        )
+        result = self.master.run_command(
+            ["ipa", "console", filename],
+        )
+        assert "ipalib.config.Env" in result.stdout_text