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Expr: make reduction nan/null more consistent (#29665)
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@ -11,7 +11,7 @@ func Sum(v *data.Field) *float64 {
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var sum float64
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var sum float64
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for i := 0; i < v.Len(); i++ {
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for i := 0; i < v.Len(); i++ {
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if f, ok := v.At(i).(*float64); ok {
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if f, ok := v.At(i).(*float64); ok {
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if f == nil {
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if f == nil || math.IsNaN(*f) {
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nan := math.NaN()
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nan := math.NaN()
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return &nan
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return &nan
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}
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}
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@ -35,7 +35,7 @@ func Min(fv *data.Field) *float64 {
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}
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}
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for i := 0; i < fv.Len(); i++ {
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for i := 0; i < fv.Len(); i++ {
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if v, ok := fv.At(i).(*float64); ok {
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if v, ok := fv.At(i).(*float64); ok {
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if v == nil {
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if v == nil || math.IsNaN(*v) {
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nan := math.NaN()
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nan := math.NaN()
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return &nan
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return &nan
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}
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}
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@ -55,7 +55,7 @@ func Max(fv *data.Field) *float64 {
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}
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}
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for i := 0; i < fv.Len(); i++ {
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for i := 0; i < fv.Len(); i++ {
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if v, ok := fv.At(i).(*float64); ok {
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if v, ok := fv.At(i).(*float64); ok {
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if v == nil {
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if v == nil || math.IsNaN(*v) {
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nan := math.NaN()
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nan := math.NaN()
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return &nan
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return &nan
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}
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}
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