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10ff4eecef
* Backend: Fix parsing of client IP address Signed-off-by: Arve Knudsen <arve.knudsen@gmail.com> Co-authored-by: Arve Knudsen <arve.knudsen@gmail.com>
45 lines
1.1 KiB
Go
45 lines
1.1 KiB
Go
package network
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import (
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"fmt"
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"net"
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"regexp"
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)
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var reIPv4AndPort = regexp.MustCompile(`^(\d+\.\d+\.\d+\.\d+):\d+$`)
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// An IPv6 address/port pair can consist of the IP address enclosed in square brackets followed by a colon and
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// a port, although the colon/port component is actually optional in practice (e.g., we may receive [::1], where
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// we should just strip off the square brackets).
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var reIPv6AndPort = regexp.MustCompile(`^\[(.+)\](:\d+)?$`)
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// GetIPFromAddress tries to get an IPv4 or IPv6 address from a host address, potentially including a port.
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func GetIPFromAddress(input string) (net.IP, error) {
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if a := net.ParseIP(input); len(a) > 0 {
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return a, nil
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}
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err := fmt.Errorf("not a valid IP address or IP address/port pair: %q", input)
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// It could potentially be an IP address/port pair
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var addr string
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ms := reIPv4AndPort.FindStringSubmatch(input)
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if len(ms) == 0 {
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ms := reIPv6AndPort.FindStringSubmatch(input)
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if len(ms) == 0 {
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return nil, err
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}
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addr = ms[1]
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} else {
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// Strip off port
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addr = ms[1]
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}
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if a := net.ParseIP(addr); len(a) > 0 {
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return a, nil
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}
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return nil, err
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}
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