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a333c31ea8
Discovered implementation issues with the set utilities used in the explore section after adding some tests. Added tests to reinforce the expected behaviour of the utility functions. Related: #13522
53 lines
2.0 KiB
TypeScript
53 lines
2.0 KiB
TypeScript
import { equal, intersect } from './set';
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describe('equal', () => {
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it('returns false for two sets of differing sizes', () => {
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const s1 = new Set([1, 2, 3]);
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const s2 = new Set([4, 5, 6, 7]);
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expect(equal(s1, s2)).toBe(false);
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});
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it('returns false for two sets where one is a subset of the other', () => {
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const s1 = new Set([1, 2, 3]);
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const s2 = new Set([1, 2, 3, 4]);
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expect(equal(s1, s2)).toBe(false);
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});
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it('returns false for two sets with uncommon elements', () => {
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const s1 = new Set([1, 2, 3, 4]);
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const s2 = new Set([1, 2, 5, 6]);
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expect(equal(s1, s2)).toBe(false);
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});
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it('returns false for two deeply equivalent sets', () => {
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const s1 = new Set([{ a: 1 }, { b: 2 }, { c: 3 }, { d: 4 }]);
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const s2 = new Set([{ a: 1 }, { b: 2 }, { c: 3 }, { d: 4 }]);
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expect(equal(s1, s2)).toBe(false);
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});
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it('returns true for two sets with the same elements', () => {
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const s1 = new Set([1, 2, 3, 4]);
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const s2 = new Set([4, 3, 2, 1]);
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expect(equal(s1, s2)).toBe(true);
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});
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});
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describe('intersect', () => {
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it('returns an empty set for two sets without any common elements', () => {
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const s1 = new Set([1, 2, 3, 4]);
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const s2 = new Set([5, 6, 7, 8]);
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expect(intersect(s1, s2)).toEqual(new Set());
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});
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it('returns an empty set for two deeply equivalent sets', () => {
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const s1 = new Set([{ a: 1 }, { b: 2 }, { c: 3 }, { d: 4 }]);
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const s2 = new Set([{ a: 1 }, { b: 2 }, { c: 3 }, { d: 4 }]);
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expect(intersect(s1, s2)).toEqual(new Set());
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});
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it('returns a set containing common elements between two sets of the same size', () => {
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const s1 = new Set([1, 2, 3, 4]);
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const s2 = new Set([5, 2, 7, 4]);
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expect(intersect(s1, s2)).toEqual(new Set([2, 4]));
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});
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it('returns a set containing common elements between two sets of differing sizes', () => {
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const s1 = new Set([1, 2, 3, 4]);
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const s2 = new Set([5, 4, 3, 2, 1]);
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expect(intersect(s1, s2)).toEqual(new Set([1, 2, 3, 4]));
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});
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});
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