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Correct documentation of why we use operator[] to initialize map.

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This commit updates the source code comment about using operator[] to
initialize the unordered map. Thanks to Bard's persistence we found
out that the cause is not the construction of the key value of type
std::string from const char* but the mapped type being a (mutable)
char* (due to C?).

This completes the PR #784.
This commit is contained in:
Markus Blatt
2015-04-14 09:31:33 +02:00
parent 236718cff9
commit 16d05fcc93
1 changed files with 4 additions and 2 deletions
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6
opm/core/linalg/LinearSolverPetsc.cpp
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@@ -38,8 +38,10 @@ namespace{
: default_type_(default_type) : default_type_(default_type)
{ {
// g++-4.4 has problems converting const char* to char* // g++-4.4 has problems converting const char* to char*
// which it thinks is needed for constructing std::string. // The problem is caused by the mapped type being PCType
// Using operator[] circumvents this problem. // which (at least in PETSc 3.2) is char* because of C
// (in the header there is "#define PCType character*(80)").
// and the KSP... defines being const char* (because of C++).
type_map_["richardson"] = KSPRICHARDSON; type_map_["richardson"] = KSPRICHARDSON;
// Not available in PETSC 3.2 on Debian // Not available in PETSC 3.2 on Debian
//type_map_["chebyshev"] = KSPCHEBYSHEV; //type_map_["chebyshev"] = KSPCHEBYSHEV;