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EclNewtonMethod: make the exponent of the tolerance scaling settable by a parameter

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the parameter is called `EclNewtonSumToleranceExponent`. if it is set
to 1, the specified tolerance will be used directly. (this is not
desireable in the general case though, because at the same result
quality, the sum error for large reservoirs can be larger than for
small ones.)
This commit is contained in:
Andreas Lauser 2019-01-11 11:18:06 +01:00
parent 0492796e85
commit c2377e7b10
2 changed files with 17 additions and 9 deletions
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18
ebos/eclnewtonmethod.hh
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@ -38,6 +38,7 @@ BEGIN_PROPERTIES
NEW_PROP_TAG(EclNewtonSumTolerance);
NEW_PROP_TAG(EclNewtonStrictIterations);
NEW_PROP_TAG(EclNewtonRelaxedVolumeFraction);
NEW_PROP_TAG(EclNewtonSumToleranceExponent);
NEW_PROP_TAG(EclNewtonRelaxedTolerance);
END_PROPERTIES
@ -104,6 +105,9 @@ public:
"The fraction of the pore volume of the reservoir "
"where the volumetric error may be voilated during "
"strict Newton iterations.");
EWOMS_REGISTER_PARAM(TypeTag, Scalar, EclNewtonSumToleranceExponent,
"The the exponent used to scale the sum tolerance by "
"the total pore volume of the reservoir.");
EWOMS_REGISTER_PARAM(TypeTag, Scalar, EclNewtonRelaxedTolerance,
"The maximum error which the volumetric residual "
"may exhibit if it is in a 'relaxed' "
@ -191,15 +195,11 @@ public:
for (unsigned eqIdx = 0; eqIdx < numEq; ++eqIdx)
errorSum_ = std::max(std::abs(componentSumError[eqIdx]), errorSum_);
// update the sum tolerance: larger reservoirs can tolerate a higher amount of
// mass lost per time step than smaller ones! since this is not linear, we use
// the cube root of the overall pore volume, i.e., the value specified by the
// NewtonSumTolerance parameter is the "incorrect" mass per timestep for an
// reservoir that exhibits 1 m^3 of pore volume. A reservoir with a total pore
// volume of 10^3 m^3 will tolerate 10 times as much.
sumTolerance_ =
EWOMS_GET_PARAM(TypeTag, Scalar, EclNewtonSumTolerance)
* std::cbrt(sumPv);
// scale the tolerance for the total error with the pore volume. by default, the
// exponent is 1/3, i.e., cubic root.
Scalar x = EWOMS_GET_PARAM(TypeTag, Scalar, EclNewtonSumTolerance);
Scalar y = EWOMS_GET_PARAM(TypeTag, Scalar, EclNewtonSumToleranceExponent);
sumTolerance_ = x*std::pow(sumPv, y);
// make sure that the error never grows beyond the maximum
// allowed one

8
ebos/eclproblem.hh
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@ -244,6 +244,14 @@ SET_SCALAR_PROP(EclBaseProblem, NewtonRawTolerance, 1e-2);
// will tolerate larger residuals.
SET_SCALAR_PROP(EclBaseProblem, EclNewtonSumTolerance, 1e-4);
// set the exponent for the volume scaling of the sum tolerance: larger reservoirs can
// tolerate a higher amount of mass lost per time step than smaller ones! since this is
// not linear, we use the cube root of the overall pore volume by default, i.e., the
// value specified by the NewtonSumTolerance parameter is the "incorrect" mass per
// timestep for an reservoir that exhibits 1 m^3 of pore volume. A reservoir with a total
// pore volume of 10^3 m^3 will tolerate 10 times as much.
SET_SCALAR_PROP(EclBaseProblem, EclNewtonSumToleranceExponent, 1.0/3.0);
// set number of Newton iterations where the volumetric residual is considered for
// convergence
SET_INT_PROP(EclBaseProblem, EclNewtonStrictIterations, 8);