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since f(x) = 1 + 0.5*g(x)*g(x) the derivative is f'(x) = 0 + 2*0.5*g(x) * g'(x) = g(x)*g'(x) note that the previous incorrect values do not affect the quality of the obtained results (if the tolerance of the non-linear solver is chosen to be small enough), but it may have deteriorated convergence rates. |
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.. | ||
pvt | ||
rock | ||
satfunc | ||
BlackoilPhases.hpp | ||
BlackoilPropertiesBasic.cpp | ||
BlackoilPropertiesBasic.hpp | ||
BlackoilPropertiesFromDeck.cpp | ||
BlackoilPropertiesFromDeck.hpp | ||
BlackoilPropertiesInterface.hpp | ||
IncompPropertiesBasic.cpp | ||
IncompPropertiesBasic.hpp | ||
IncompPropertiesFromDeck.cpp | ||
IncompPropertiesFromDeck.hpp | ||
IncompPropertiesInterface.hpp | ||
IncompPropertiesShadow_impl.hpp | ||
IncompPropertiesShadow.hpp | ||
IncompPropertiesSinglePhase.cpp | ||
IncompPropertiesSinglePhase.hpp | ||
phaseUsageFromDeck.hpp |